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network: optimize optimalN for small networks

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Consider 10-node network. FanOut is 6 for it. optimalN is 12. But it's a
10-node network, you can't have more than 9 peers there. So adjust the formula
for netSize-1.

Signed-off-by: Roman Khimov <roman@nspcc.ru>
This commit is contained in:
Roman Khimov 2024-12-05 22:29:42 +03:00
parent 9a3923097b
commit d69f8ebbab
1 changed files with 2 additions and 2 deletions
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4
pkg/network/server.go
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@ -482,7 +482,7 @@ func (s *Server) run() {
var (
netSize = s.discovery.NetworkSize()
// "Optimal" number of peers.
optimalN = s.discovery.GetFanOut() * 2
optimalN = min(s.discovery.GetFanOut()*2, netSize-1)
// Real number of peers.
peerN = s.HandshakedPeersCount()
// Timeout value for the next peerTimer, long one by default.
@ -494,7 +494,7 @@ func (s *Server) run() {
s.discovery.RequestRemote(s.AttemptConnPeers)
// Check/retry new connections soon.
peerT = s.ProtoTickInterval
} else if s.MinPeers > 0 && loopCnt%s.MinPeers == 0 && optimalN > peerN && optimalN < s.MaxPeers && optimalN < netSize {
} else if s.MinPeers > 0 && loopCnt%s.MinPeers == 0 && optimalN > peerN && optimalN < s.MaxPeers {
// Having some number of peers, but probably can get some more, the network is big.
// It also allows to start picking up new peers proactively, before we suddenly have <s.MinPeers of them.
s.discovery.RequestRemote(min(s.AttemptConnPeers, optimalN-peerN))