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compiler: copy structs when passing as arguments
In Go structs must be copied when used as arguments. To do so we must clone struct on VM level. This is done by appending this struct to an intermediate array.
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2 changed files with 50 additions and 0 deletions
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@ -793,6 +793,18 @@ func (c *codegen) Visit(node ast.Node) ast.Visitor {
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// Handle the arguments
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for _, arg := range args {
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ast.Walk(c, arg)
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typ := c.typeOf(arg)
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_, ok := typ.Underlying().(*types.Struct)
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if ok && !isInteropPath(typ.String()) {
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// To clone struct fields we create a new array and append struct to it.
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// This way even non-pointer struct fields will be copied.
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emit.Opcode(c.prog.BinWriter, opcode.NEWARRAY0)
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emit.Opcode(c.prog.BinWriter, opcode.DUP)
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emit.Opcode(c.prog.BinWriter, opcode.ROT)
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emit.Opcode(c.prog.BinWriter, opcode.APPEND)
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emit.Opcode(c.prog.BinWriter, opcode.PUSH0)
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emit.Opcode(c.prog.BinWriter, opcode.PICKITEM)
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}
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}
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// Do not swap for builtin functions.
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if !isBuiltin {
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@ -28,3 +28,41 @@ func TestPointerDereference(t *testing.T) {
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func setA(s Foo, a int) { s.A = a }`
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eval(t, src, big.NewInt(4))
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}
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func TestStructArgCopy(t *testing.T) {
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t.Run("Simple", func(t *testing.T) {
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src := `package foo
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type Foo struct { A int }
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func Main() int {
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f := Foo{A: 4}
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setA(f, 3)
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return f.A
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}
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func setA(s Foo, a int) { s.A = a }`
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eval(t, src, big.NewInt(4))
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})
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t.Run("StructField", func(t *testing.T) {
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src := `package foo
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type Bar struct { A int }
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type Foo struct { B Bar }
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func Main() int {
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f := Foo{B: Bar{A: 4}}
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setA(f, 3)
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return f.B.A
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}
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func setA(s Foo, a int) { s.B.A = a }`
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eval(t, src, big.NewInt(4))
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})
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t.Run("StructPointerField", func(t *testing.T) {
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src := `package foo
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type Bar struct { A int }
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type Foo struct { B *Bar }
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func Main() int {
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f := Foo{B: &Bar{A: 4}}
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setA(f, 3)
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return f.B.A
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}
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func setA(s Foo, a int) { s.B.A = a }`
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eval(t, src, big.NewInt(3))
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})
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}
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