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https://github.com/nspcc-dev/neo-go.git
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29586f2aa7
Refactor HaveInputsDuplicate() out of the core and Blockchain, it doesn't depend on the Blockchain state. Make it more efficient.
88 lines
2.1 KiB
Go
88 lines
2.1 KiB
Go
package transaction
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import (
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"sort"
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"github.com/CityOfZion/neo-go/pkg/io"
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"github.com/CityOfZion/neo-go/pkg/util"
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)
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// Input represents a Transaction input (CoinReference).
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type Input struct {
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// The hash of the previous transaction.
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PrevHash util.Uint256 `json:"txid"`
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// The index of the previous transaction.
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PrevIndex uint16 `json:"vout"`
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}
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// DecodeBinary implements Serializable interface.
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func (in *Input) DecodeBinary(br *io.BinReader) {
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br.ReadBytes(in.PrevHash[:])
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in.PrevIndex = br.ReadU16LE()
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}
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// EncodeBinary implements Serializable interface.
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func (in *Input) EncodeBinary(bw *io.BinWriter) {
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bw.WriteBytes(in.PrevHash[:])
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bw.WriteU16LE(in.PrevIndex)
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}
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// MapInputsToSorted maps given slice of inputs into a new slice of pointers
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// to inputs sorted by their PrevHash and PrevIndex.
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func MapInputsToSorted(ins []Input) []*Input {
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ptrs := make([]*Input, len(ins))
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for i := range ins {
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ptrs[i] = &ins[i]
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}
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sort.Slice(ptrs, func(i, j int) bool {
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hashcmp := ptrs[i].PrevHash.CompareTo(ptrs[j].PrevHash)
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if hashcmp == 0 {
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return ptrs[i].PrevIndex < ptrs[j].PrevIndex
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}
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return hashcmp < 0
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})
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return ptrs
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}
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// GroupInputsByPrevHash groups all TX inputs by their previous hash into
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// several slices (which actually are subslices of one new slice with pointers).
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// Each of these slices contains at least one element.
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func GroupInputsByPrevHash(ins []Input) [][]*Input {
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if len(ins) == 0 {
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return nil
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}
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ptrs := MapInputsToSorted(ins)
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var first int
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res := make([][]*Input, 0)
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currentHash := ptrs[0].PrevHash
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for i := range ptrs {
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if !currentHash.Equals(ptrs[i].PrevHash) {
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res = append(res, ptrs[first:i])
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first = i
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currentHash = ptrs[i].PrevHash
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}
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}
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res = append(res, ptrs[first:])
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return res
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}
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// HaveDuplicateInputs checks inputs for duplicates and returns true if there are
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// any.
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func HaveDuplicateInputs(ins []Input) bool {
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if len(ins) < 2 {
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return false
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}
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if len(ins) == 2 {
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return ins[0] == ins[1]
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}
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ptrs := MapInputsToSorted(ins)
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for i := 1; i < len(ptrs); i++ {
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if *ptrs[i] == *ptrs[i-1] {
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return true
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}
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}
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return false
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}
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