compiler: abstract out emitReverse
Extract logic of reversing top n items of the stack in a separate function.
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268cad5c06
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1 changed files with 17 additions and 11 deletions
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@ -540,17 +540,7 @@ func (c *codegen) Visit(node ast.Node) ast.Visitor {
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}
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}
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// Do not swap for builtin functions.
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// Do not swap for builtin functions.
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if !isBuiltin {
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if !isBuiltin {
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if numArgs == 2 {
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c.emitReverse(numArgs)
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emit.Opcode(c.prog.BinWriter, opcode.SWAP)
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} else if numArgs == 3 {
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emit.Int(c.prog.BinWriter, 2)
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emit.Opcode(c.prog.BinWriter, opcode.XSWAP)
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} else {
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for i := 1; i < numArgs; i++ {
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emit.Int(c.prog.BinWriter, int64(i))
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emit.Opcode(c.prog.BinWriter, opcode.ROLL)
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}
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}
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}
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}
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// Check builtin first to avoid nil pointer on funcScope!
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// Check builtin first to avoid nil pointer on funcScope!
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@ -680,6 +670,22 @@ func (c *codegen) Visit(node ast.Node) ast.Visitor {
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return c
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return c
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}
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}
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// emitReverse reverses top num items of the stack.
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func (c *codegen) emitReverse(num int) {
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switch num {
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case 2:
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emit.Opcode(c.prog.BinWriter, opcode.SWAP)
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case 3:
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emit.Int(c.prog.BinWriter, 2)
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emit.Opcode(c.prog.BinWriter, opcode.XSWAP)
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default:
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for i := 1; i < num; i++ {
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emit.Int(c.prog.BinWriter, int64(i))
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emit.Opcode(c.prog.BinWriter, opcode.ROLL)
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}
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}
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}
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func (c *codegen) getEqualityOpcode(expr ast.Expr) opcode.Opcode {
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func (c *codegen) getEqualityOpcode(expr ast.Expr) opcode.Opcode {
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t, ok := c.typeInfo.Types[expr].Type.Underlying().(*types.Basic)
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t, ok := c.typeInfo.Types[expr].Type.Underlying().(*types.Basic)
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if ok && t.Info()&types.IsNumeric != 0 {
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if ok && t.Info()&types.IsNumeric != 0 {
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