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compiler: remove CompileWithDebugInfo

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It is a simple wrapper over `CompileWithOptions` which we don't really
need. Custom options can be specified explicitly instead of using some
random default. This default was introduced in 1578904da, however tests
written there use `CompileWithOptions` and all other tests
pass on that commit even without this default.

Signed-off-by: Evgeniy Stratonikov <evgeniy@nspcc.ru>
This commit is contained in:
Evgeniy Stratonikov 2021-07-26 15:34:07 +03:00
parent 46f623a48f
commit 8af9c870b1
14 changed files with 26 additions and 33 deletions
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4
pkg/compiler/syscall_test.go
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@ -139,7 +139,7 @@ func runSyscallTestCase(t *testing.T, ic *interop.Context, goName string, tc sys
}
ss := strings.Split(goName, ".")
src := fmt.Sprintf(srcTmpl, ss[0], goName, strings.Join(tc.params, ", "))
b, _, err := compiler.CompileWithDebugInfo("foo", strings.NewReader(src))
b, _, err := compiler.CompileWithOptions("foo", strings.NewReader(src), nil)
require.NoError(t, err)
v := ic.SpawnVM()
@ -198,7 +198,7 @@ func TestNotify(t *testing.T) {
runtime.Notify("long event12345678901234567890123")
}`
_, _, err := compiler.CompileWithDebugInfo("foo.go", strings.NewReader(src))
_, _, err := compiler.CompileWithOptions("foo.go", strings.NewReader(src), nil)
require.Error(t, err)
})
}