Rename backend subdir 'blobs' to 'data'

This commit is contained in:
Alexander Neumann 2014-11-16 13:22:19 +01:00
parent b403769ae8
commit 804cebde67
8 changed files with 22 additions and 31 deletions

View file

@ -19,15 +19,6 @@ import (
)
const (
// dirMode = 0700
// blobPath = "blobs"
// snapshotPath = "snapshots"
// treePath = "trees"
// lockPath = "locks"
// keyPath = "keys"
// tempPath = "tmp"
// versionFileName = "version"
tempfileRandomSuffixLength = 10
)
@ -83,7 +74,7 @@ func OpenSFTP(dir string, program string, args ...string) (*SFTP, error) {
// test if all necessary dirs and files are there
items := []string{
dir,
filepath.Join(dir, blobPath),
filepath.Join(dir, dataPath),
filepath.Join(dir, snapshotPath),
filepath.Join(dir, treePath),
filepath.Join(dir, lockPath),
@ -139,7 +130,7 @@ func CreateSFTP(dir string, program string, args ...string) (*SFTP, error) {
versionFile := filepath.Join(dir, versionFileName)
dirs := []string{
dir,
filepath.Join(dir, blobPath),
filepath.Join(dir, dataPath),
filepath.Join(dir, snapshotPath),
filepath.Join(dir, treePath),
filepath.Join(dir, lockPath),
@ -160,7 +151,7 @@ func CreateSFTP(dir string, program string, args ...string) (*SFTP, error) {
}
}
// create paths for blobs, refs and temp
// create paths for data, refs and temp blobs
for _, d := range dirs {
// TODO: implement client.MkdirAll() and set mode to dirMode
_, err = sftp.c.Lstat(d)
@ -241,8 +232,8 @@ func (r *SFTP) renameFile(filename string, t Type, id ID) error {
func (r *SFTP) dir(t Type) string {
var n string
switch t {
case Blob:
n = blobPath
case Data:
n = dataPath
case Snapshot:
n = snapshotPath
case Tree: