cache: Just try to open cache entry without calling stat first

Instead of first checking whether a file is in the repository cache and
then opening it, we just can open the file. This saves one stat call. If
the file is in the cache, everything is fine and otherwise the code
follows its normal fallback path.

internal/cache/backend.go

@@ -160,8 +160,7 @@ func (b *Backend) Load(ctx context.Context, h restic.Handle, length int, offset
 		debug.Log("downloading %v finished", h)
 	}
 
-	if b.Cache.Has(h) {
-		debug.Log("Load(%v, %v, %v) from cache", h, length, offset)
+	// try loading from cache without checking that the handle is actually cached
 	rd, err := b.Cache.load(h, length, offset)
 	if err == nil {
 		err = consumer(rd)
@@ -172,7 +171,6 @@ func (b *Backend) Load(ctx context.Context, h restic.Handle, length int, offset
 		return rd.Close()
 	}
 	debug.Log("error loading %v from cache: %v", h, err)
-	}
 
 	// if we don't automatically cache this file type, fall back to the backend
 	if !autoCacheTypes(h) {
@@ -181,7 +179,7 @@ func (b *Backend) Load(ctx context.Context, h restic.Handle, length int, offset
 	}
 
 	debug.Log("auto-store %v in the cache", h)
-	err := b.cacheFile(ctx, h)
+	err = b.cacheFile(ctx, h)
 	if err == nil {
 		return b.loadFromCacheOrDelegate(ctx, h, length, offset, consumer)
 	}

internal/cache/file.go

@@ -43,7 +43,7 @@ type readCloser struct {
 // given handle. rd must be closed after use. If an error is returned, the
 // ReadCloser is nil.
 func (c *Cache) load(h restic.Handle, length int, offset int64) (io.ReadCloser, error) {
-	debug.Log("Load from cache: %v", h)
+	debug.Log("Load(%v, %v, %v) from cache", h, length, offset)
 	if !c.canBeCached(h.Type) {
 		return nil, errors.New("cannot be cached")
 	}