[#447] pilorama: Do not undo log for create ops

```
goos: linux
goarch: amd64
cpu: 11th Gen Intel(R) Core(TM) i5-1135G7 @ 2.40GHz
         │     old      │                 new                  │
         │    sec/op    │    sec/op     vs base                │
Create-8   36.48µ ± 11%   30.34µ ± 14%  -16.84% (p=0.000 n=10)

         │     old      │                 new                  │
         │     B/op     │     B/op      vs base                │
Create-8   43.01Ki ± 4%   37.78Ki ± 5%  -12.15% (p=0.000 n=10)

         │    old     │                new                 │
         │ allocs/op  │ allocs/op   vs base                │
Create-8   166.0 ± 3%   146.0 ± 3%  -12.05% (p=0.000 n=10)
```

Signed-off-by: Evgenii Stratonikov <e.stratonikov@yadro.com>
This commit is contained in:
Evgenii Stratonikov 2023-04-26 15:06:16 +03:00 committed by Evgenii Stratonikov
parent dd3874eff1
commit b4ce0b0412

View file

@ -1,6 +1,7 @@
package pilorama
import (
"encoding/binary"
"sort"
"sync"
"time"
@ -49,10 +50,67 @@ func (b *batch) run() {
sort.Slice(b.operations, func(i, j int) bool {
return b.operations[i].Time < b.operations[j].Time
})
b.operations = removeDuplicatesInPlace(b.operations)
// Our main use-case is addition of new items. In this case,
// we do not need to perform undo()/redo(), just do().
// https://github.com/trvedata/move-op/blob/6c23447c12a7862ff31b7fc2205f6c90fbdb9dc0/proof/Move_Create.thy#L259
//
// For this optimization to work we need to ensure three things:
// 1. The node itself is not yet in tree.
// 2. The node is not a parent. This case is not mentioned in the article, because
// they consider a "static order" (perform all CREATE operations before MOVE).
// We need this because if node _is_ a parent, we could violate (3) for some late operation.
// See TestForest_ApplySameOperation for details.
// 3. Parent of each operation is already in tree.
var parents map[uint64]struct{}
var cKey [17]byte
var slow bool
for i := range b.operations {
_, _, _, inTree := b.forest.getState(bTree, stateKey(cKey[:], b.operations[i].Child))
if inTree {
slow = true
break
}
key := childrenKey(cKey[:], b.operations[i].Child, 0)
k, _ := bTree.Cursor().Seek(key)
if len(k) == 17 && binary.LittleEndian.Uint64(k[1:]) == b.operations[i].Child {
slow = true
break
}
if b.operations[i].Parent == RootID {
continue
} else if parents == nil {
// Attaching key only to root is done frequently,
// no allocations are performed unless necessary.
parents = make(map[uint64]struct{})
} else if _, ok := parents[b.operations[i].Parent]; ok {
continue
}
p := b.operations[i].Parent
_, ts, _, inTree := b.forest.getState(bTree, stateKey(cKey[:], p))
if !inTree || b.operations[0].Time < ts {
slow = true
break
}
parents[b.operations[i].Parent] = struct{}{}
}
if slow {
var lm Move
return b.forest.applyOperation(bLog, bTree, b.operations, &lm)
}
var key [17]byte
for i := range b.operations {
if err := b.forest.do(bLog, bTree, key[:], b.operations[i]); err != nil {
return err
}
}
return nil
})
for i := range b.results {
b.results[i] <- err