frostfs-testcases/robot/resources/lib/python/storage_policy.py
anastasia prasolova e4c1c23ddd [#205] storage policy validation reconsidered
Signed-off-by: anastasia prasolova <anastasia@nspcc.ru>
2022-05-26 16:51:05 +03:00

79 lines
2.9 KiB
Python

#!/usr/bin/python3
'''
This module contains keywords which are used for asserting
that storage policies are kept.
'''
from common import NEOFS_NETMAP
import complex_object_actions
import neofs_verbs
from robot.api.deco import keyword
ROBOT_AUTO_KEYWORDS = False
@keyword('Get Object Copies')
def get_object_copies(complexity: str, wallet: str, cid: str, oid: str):
"""
The function performs requests to all nodes of the container and
finds out if they store a copy of the object. The procedure is
different for simple and complex object, so the function requires
a sign of object complexity.
Args:
complexity (str): the tag of object size and complexity,
[Simple|Complex]
wallet (str): the path to the wallet on whose behalf the
copies are got
cid (str): ID of the container
oid (str): ID of the Object
Returns:
(int): the number of object copies in the container
"""
return (get_simple_object_copies(wallet, cid, oid) if complexity == "Simple"
else get_complex_object_copies(wallet, cid, oid))
@keyword('Get Simple Object Copies')
def get_simple_object_copies(wallet: str, cid: str, oid: str):
"""
To figure out the number of a simple object copies, only direct
HEAD requests should be made to the every node of the container.
We consider non-empty HEAD response as a stored object copy.
Args:
wallet (str): the path to the wallet on whose behalf the
copies are got
cid (str): ID of the container
oid (str): ID of the Object
Returns:
(int): the number of object copies in the container
"""
copies = 0
for node in NEOFS_NETMAP:
response = neofs_verbs.head_object(wallet, cid, oid,
endpoint=node,
is_direct=True)
if response:
copies += 1
return copies
@keyword('Get Complex Object Copies')
def get_complex_object_copies(wallet: str, cid: str, oid: str):
"""
To figure out the number of a complex object copies, we firstly
need to retrieve its Last object. We consider that the number of
complex object copies is equal to the number of its last object
copies. When we have the Last object ID, the task is reduced
to getting simple object copies.
Args:
wallet (str): the path to the wallet on whose behalf the
copies are got
cid (str): ID of the container
oid (str): ID of the Object
Returns:
(int): the number of object copies in the container
"""
last_oid = complex_object_actions.get_last_object(wallet, cid, oid)
return get_simple_object_copies(wallet, cid, last_oid)