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[#472] tree: Don't use sorted GetSubTree for nodes without FileName

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Sorted GetSubTree doesn't return nodes without FileName attribute
if there are more than 1000 nodes in subtree

Signed-off-by: Denis Kirillov <d.kirillov@yadro.com>
This commit is contained in:
Denis Kirillov 2024-08-21 15:10:34 +03:00 • committed by Alexey Vanin
parent 0637133c61
commit d76c4fe2a2
4 changed files with 22 additions and 10 deletions
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6
pkg/service/tree/tree_client_in_memory.go
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@ -234,7 +234,7 @@ func (c *ServiceClientMemory) GetNodes(_ context.Context, p *GetNodesParams) ([]
return res2, nil
}
func (c *ServiceClientMemory) GetSubTree(_ context.Context, bktInfo *data.BucketInfo, treeID string, rootID []uint64, depth uint32) ([]NodeResponse, error) {
func (c *ServiceClientMemory) GetSubTree(_ context.Context, bktInfo *data.BucketInfo, treeID string, rootID []uint64, depth uint32, sort bool) ([]NodeResponse, error) {
cnr, ok := c.containers[bktInfo.CID.EncodeToString()]
if !ok {
return nil, nil
@ -254,6 +254,10 @@ func (c *ServiceClientMemory) GetSubTree(_ context.Context, bktInfo *data.Bucket
return nil, ErrNodeNotFound
}
if sort {
sortNode(tr.treeData)
}
// we depth-1 in case of uint32 and 0 as mark to get all subtree leads to overflow and depth is getting quite big to walk all tree levels
return node.listNodes(nil, depth-1), nil
}